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Books and other education websites provide "matter-of-fact" knowledge. Instead, nubtrek provides a thought-process to discover knowledge.

In each of the topic, the outline of the thought-process, for that topic, is provided for learners and educators.

Read in the blogs more about the unique learning experience at nubtrek.continue

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Multiplication Simplified Using Algebraic Identities

» `81^2 = (80+1)^2` *`(a+b)^2 = a^2+2ab+b^2`*

» `78^2 = (80-2)^2` *`(a-b)^2 = a^2-2ab+b^2`*

» `84xx 76 = (80+4)(80-4)` *`(a+b)(a-b) = a^2-b^2`*

» `83xx86 = (80+3)(80+6)` *`(x+a)(x+b)``= x^2+(a+b)x+ab`*

*plain and simple summary*

nub

*plain and simple summary*

nub

dummy

algebraic identity helps to simplify some numerical multiplications.

*simple steps to build the foundation*

trek

*simple steps to build the foundation*

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The algebraic identities of square can be used to simplify multiplication of numbers or square of numbers.

Starting on learning "Multiplication Simplified Using Algebraic Identities". ;; The algebraic identities of square can be used to simplify multiplication of numbers or square of numbers.

Which of the following is true to compute `71^2`?

- Using `(a+b)^2` identity to calculate `(70+1)^2`
- algebraic identities cannot be used for numbers

The answer is 'Using `(a+b)^2` identity to calculate `(70+1)^2`'

To compute `71^2` the `(a+b)^2` identity is used to simplify the multiplication.

`71^2`

`=(70+1)^2`

`=70^2+2xx70xx1+1^2`

`=4900 + 140 + 1`

`=5041`

Which of the following is true to compute `69^2`?

- Using `(a-b)^2` identity to calculate `(70-1)^2`
- algebraic identities cannot be used for numbers

The answer is 'Using `(a-b)^2` identity to calculate `(70-1)^2`'

To compute `69^2` the `(a-b)^2` identity is used to simplify multiplication.

`69^2`

`=(70-1)^2`

`=70^2-2xx70xx1+1^2`

`=4900 - 140 + 1`

`=4761`

Which of the following is true to compute `73 xx 67`?

- Using `(a+b)(a-b)` identity to calculate `(70+3)(70-3)`
- algebraic identities cannot be used for numbers

The answer is 'Using `(a+b)(a-b)` identity to calculate `(70+3)(70-3)`'

To compute `73xx67` the `(a+b)(a-b)` identity is used to simplify the multiplication.

`73xx67`

`=(70+3)(70-3)`

`=70^2-3^2`

`=4900 -9`

`=4891`

*comprehensive information for quick review*

Jogger

*comprehensive information for quick review*

Jogger

dummy

**Using Algebraic Identities in Numerical Multiplication**: The variables of algebraic identities can be substituted with numbers and the identities can be used if multiplication becomes simpler.

*practice questions to master the knowledge*

Exercise

*practice questions to master the knowledge*

Exercise

Compute `52^2` using an algebraic identity.

- `(50+2)^2` `=2500+200+4`
- `(5+2)^2` `=25+20+4`

The answer is '`(50+2)^2` `=2500+200+4`'

Compute `87^2` using an algebraic identity.

- `(90-3)^2` `=8100-540+9`
- `(8+7)^2` `=64+112+49`

The answer is '`(90-3)^2` `=8100-540+9`'

Compute `52xx48` using an algebraic identity.

- `(50+2)(50-2)` `=2500-4`
- `(5+2)48` `=5xx48+2 xx 48`

The answer is '`(50+2)(50-2)` `=2500-4`'

*your progress details*

Progress

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Progress

which of the following is true to compute 71 squared?

using;squared;calculate

using a+b squared identity to calculate 70 + 1 squared

algebraic;cannot;can;not;used

algebraic identities cannot be used for numbers

The answer is "using a+b squared identity to calculate 70 + 1 squared"

To compute 71 squared, a + b whole squared identity is used to simplify the multiplication.

Compute 52 squared using an algebraic identity.

1

2

The answer is "50 + 2 whole squared"

which of the following is true to compute 69 squared?

using;squared;calculate

using a-b squared identity to calculate 70 - 1 squared

algebraic;cannot;can;not;used

algebraic identities cannot be used for numbers

The answer is "using a-b squared identity to calculate 70 - 1 squared"

To compute 69 squared, a minus b whole squared identity is used to simplify the multiplication.

compute 87 squared using an algebraic identity.

1

2

The answer is "90 minus 2 whole squared"

which of the following is true to compute 73 multiplied 67?

using;multiplied;minus

using a+b multiplied a minus b identity to calculate 70 + 3 multiplied 70 minus 3

algebraic;cannot;can;not;used

algebraic identities cannot be used for numbers

The answer is "using a+b multiplied a minus b identity to calculate 70 + 3 multiplied 70 minus 3"

To compute 73 multiplied 67, a + b multiplied a minus b identity is used to simplify the multiplication.

Compute 52 multiplied 48 using an algebraic identity.

1

2

The answer is " 50 +2 multiplied 50 minus 2"

algebraic identity helps to simplify some numerical multiplications.

The variables of algebraic identities can be substituted with numbers and the identities can be used if multiplication becomes simpler.