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summary of this topic

### Basic Algebraic Identities

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Multiplication Simplified Using Algebraic Identities

The variables of algebraic identities can be substituted with numbers and the identities can be used if multiplication becomes simpler.

»  81^2 = (80+1)^2
(a+b)^2 = a^2+2ab+b^2

»  78^2 = (80-2)^2
(a-b)^2 = a^2-2ab+b^2

»  84xx 76 = (80+4)(80-4)
(a+b)(a-b) = a^2-b^2

»  83xx86 = (80+3)(80+6)
(x+a)(x+b)= x^2+(a+b)x+ab

### Multiplication Simplified Using Algebraic Identities

plain and simple summary

nub

plain and simple summary

nub

dummy

algebraic identity helps to simplify some numerical multiplications.

simple steps to build the foundation

trek

simple steps to build the foundation

trek

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The algebraic identities of square can be used to simplify multiplication of numbers or square of numbers.

Keep tapping on the content to continue learning.
Starting on learning "Multiplication Simplified Using Algebraic Identities". ;; The algebraic identities of square can be used to simplify multiplication of numbers or square of numbers.

Which of the following is true to compute 71^2?

• Using (a+b)^2 identity to calculate (70+1)^2
• algebraic identities cannot be used for numbers

The answer is 'Using (a+b)^2 identity to calculate (70+1)^2'

To compute 71^2 the (a+b)^2 identity is used to simplify the multiplication.
71^2
=(70+1)^2
=70^2+2xx70xx1+1^2
=4900 + 140 + 1
=5041

Which of the following is true to compute 69^2?

• Using (a-b)^2 identity to calculate (70-1)^2
• algebraic identities cannot be used for numbers

The answer is 'Using (a-b)^2 identity to calculate (70-1)^2'

To compute 69^2 the (a-b)^2 identity is used to simplify multiplication.
69^2
=(70-1)^2
=70^2-2xx70xx1+1^2
=4900 - 140 + 1
=4761

Which of the following is true to compute 73 xx 67?

• Using (a+b)(a-b) identity to calculate (70+3)(70-3)
• algebraic identities cannot be used for numbers

The answer is 'Using (a+b)(a-b) identity to calculate (70+3)(70-3)'

To compute 73xx67 the (a+b)(a-b) identity is used to simplify the multiplication.
73xx67
=(70+3)(70-3)
=70^2-3^2
=4900 -9
=4891

comprehensive information for quick review

Jogger

comprehensive information for quick review

Jogger

dummy

Using Algebraic Identities in Numerical Multiplication: The variables of algebraic identities can be substituted with numbers and the identities can be used if multiplication becomes simpler.

practice questions to master the knowledge

Exercise

practice questions to master the knowledge

Exercise

Compute 52^2 using an algebraic identity.

• (50+2)^2 =2500+200+4
• (5+2)^2 =25+20+4

The answer is '(50+2)^2 =2500+200+4'

Compute 87^2 using an algebraic identity.

• (90-3)^2 =8100-540+9
• (8+7)^2 =64+112+49

The answer is '(90-3)^2 =8100-540+9'

Compute 52xx48 using an algebraic identity.

• (50+2)(50-2) =2500-4
• (5+2)48 =5xx48+2 xx 48

The answer is '(50+2)(50-2) =2500-4'

Progress

Progress

which of the following is true to compute 71 squared?
using;squared;calculate
using a+b squared identity to calculate 70 + 1 squared
algebraic;cannot;can;not;used
algebraic identities cannot be used for numbers
The answer is "using a+b squared identity to calculate 70 + 1 squared"
To compute 71 squared, a + b whole squared identity is used to simplify the multiplication.
Compute 52 squared using an algebraic identity.
1
2
The answer is "50 + 2 whole squared"
which of the following is true to compute 69 squared?
using;squared;calculate
using a-b squared identity to calculate 70 - 1 squared
algebraic;cannot;can;not;used
algebraic identities cannot be used for numbers
The answer is "using a-b squared identity to calculate 70 - 1 squared"
To compute 69 squared, a minus b whole squared identity is used to simplify the multiplication.
compute 87 squared using an algebraic identity.
1
2
The answer is "90 minus 2 whole squared"
which of the following is true to compute 73 multiplied 67?
using;multiplied;minus
using a+b multiplied a minus b identity to calculate 70 + 3 multiplied 70 minus 3
algebraic;cannot;can;not;used
algebraic identities cannot be used for numbers
The answer is "using a+b multiplied a minus b identity to calculate 70 + 3 multiplied 70 minus 3"
To compute 73 multiplied 67, a + b multiplied a minus b identity is used to simplify the multiplication.
Compute 52 multiplied 48 using an algebraic identity.
1
2
The answer is " 50 +2 multiplied 50 minus 2"
algebraic identity helps to simplify some numerical multiplications.
The variables of algebraic identities can be substituted with numbers and the identities can be used if multiplication becomes simpler.

we are not perfect yet...