 Server Error

Server Not Reachable.

This may be due to your internet connection or the nubtrek server is offline.

Thought-Process to Discover Knowledge

Welcome to nubtrek.

Books and other education websites provide "matter-of-fact" knowledge. Instead, nubtrek provides a thought-process to discover knowledge.

In each of the topic, the outline of the thought-process, for that topic, is provided for learners and educators.

Read in the blogs more about the unique learning experience at nubtrek.
mathsTrigonometryTrigonometric Identities and Complementary Angles

### Pythagorean Trigonometric Identities

The relationship between trigonometric ratios per Pythagorean theorem is explained and referred as "Pythagorean Trigonometric Identities"

click on the content to continue..

For the triangle given in figure, What is sin theta? • (OP)/(OQ)
• (PQ)/(OQ)
• (PQ)/(OQ)

The answer is '(PQ)/(OQ)'

For the triangle given in figure, What is cos theta? • (OP)/(OQ)
• (OP)/(OQ)
• (PQ)/(OQ)

The answer is '(OP)/(OQ)'

For the triangle given in figure, which of the following represents Pythagoras theorem? • OP^2 + PQ^2 =OQ^2
• ((OP)/(OQ))^2 + ((PQ)/(OQ))^2 = 1
• Both the above
• Both the above

The answer is 'both the above'.

For a right angled triangle, the Pythagoras theorem is given as

(text(opposite))^2 + (text(adjacent))^2 = (text(hypotenuse))^2

If this equation is divided by (text(hypotenuse))^2 ; which of the following is the result? • ((OP)/(OQ))^2 + ((PQ)/(OQ))^2 = 1
• sin^2 theta + cos^2 theta = 1
• Both the above
• Both the above

The answer is 'both the above'.

Pythagorean Theorem states that in a right angled triangle, square of hypotenuse equals sum of squares of two arms. The trigonometric ratios are defined for right angled triangles. The relationships between trigonometric ratios per Pythagorean theorem are called "Pythagorean Trigonometric Identities".

sin^2 theta + cos^2 theta = 1

It is noted that the result is true for any value of theta. That is, if theta = 27, then sin^2 27^@ + cos^2 27^@ = 1

What does 'identity' mean?

• It is just a name.
• equality of two expressions; left and right hand side are identical
• equality of two expressions; left and right hand side are identical

Answer is 'equality of two expressions; left and right hand side are identical'.

In the Pythagorean Trigonometric Identity sin^2 theta + cos^2 theta = 1, it is stated that left hand side sin^2 theta + cos^2 theta equals the right hand side 1.

For a right angled triangle,

sin^2 theta + cos^2 theta = 1

If this equation is divided by sin^2 theta ; which of the following is the result? • cannot divide this equation by sin^2 theta
• 1+cot^2 theta = csc^2 theta
• 1+cot^2 theta = csc^2 theta

The answer is '1+cot^2 theta = csc^2 theta'.

1+cot^2 theta = csc^2 theta

For a right angled triangle,

sin^2 theta + cos^2 theta = 1

If this equation is divided by cos^2 theta ; which of the following is the result? • cannot divide this equation by cos^2 theta
• tan^2 theta + 1 = sec^2 theta
• tan^2 theta + 1 = sec^2 theta

The answer is 'tan^2 theta + 1 = sec^2 theta'.

tan^2 theta + 1 = sec^2 theta

Pythagorean Trigonometric Identities:

For any theta,

sin^2 theta + cos^2 theta = 1

1+cot^2 theta = csc^2 theta

tan^2 theta + 1 = sec^2 theta

Note that this need not me memorized, connect these to the Pythogoras theorem and quickly derive when required.

Solved Exercise Problem:

What is the value of 1-sin^2 theta?

• cos^2 theta
• cos^2 theta
• the question is incomplete to find an answer

The answer is 'cos^2 theta'.

This is derived from the Pythagorean trigonometric identity sin^2 theta + cos^2 theta = 1

Solved Exercise Problem:

What is the value of sec^2 theta - 1?

• tan^2 theta
• tan^2 theta
• cot^2 theta

The answer is 'tan^2 theta'.

This is derived from the Pythagorean trigonometric identity tan^2 theta + 1 = sec^2 theta

Solved Exercise Problem:

What is the value of csc^2 theta-cot^2 theta?

• cos^2 theta
• 1
• 1

The answer is '1'.

This is derived from the Pythagorean trigonometric identity 1 + cot^2 theta = csc^2 theta

switch to slide-show version