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Books and other education websites provide "matter-of-fact" knowledge. Instead, nubtrek provides a thought-process to discover knowledge.

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Books and other education websites provide "matter-of-fact" knowledge. Instead, nubtrek provides a thought-process to discover knowledge.

In each of the topic, the outline of the thought-process, for that topic, is provided for learners and educators.

Read in the blogs more about the unique learning experience at nubtrek.continue

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Repeated addition of a Vector

» Repeated addition is generalized to **Multiplication of a vector by Scalar**

» Components are multiplied by scalar

→ `vec p = ai + bj + ck`

→ `lambda vec p = lambda a i + lambda b j + lambda c k`

*plain and simple summary*

nub

*plain and simple summary*

nub

dummy

When vector is multiplied by a scalar, the vector scales up or down proportionally.

*simple steps to build the foundation*

trek

*simple steps to build the foundation*

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In this page repeated addition of vectors is explained.

Starting on learning "Repeated addition of Vectors". ;; In this page repeated addition of vectors is explained.

We have learned about addition of two or more vectors. Consider a vector being repeatedly added to itself. What is the result of the addition `vec p + vec p`?

- sum `= 2 times vec p`
- component form is required to find the sum
- directional cosines are required to find the sum
- sum `=2 times |vec p|`

The answer is 'sum `= 2 times vec p`'. If `vec p = ai+bj+ck` then `vec p + vec p = 2ai+2bj+2ck`. This equals `2 times vec p`.

Repeated addition can be generalized to multiplication of vector by a scalar. Scalar multiplier is denoted with `lambda` to identify differently to the component values `a, b, c`. Note that the scalar multiplier and component values are real numbers. What is the result of `lambda vec p` if `vec p = ai+bj+ck`?

- `lambda ai+bj+ck`
- `lambda i+ lambda j + lambda k`
- `lambda ai+ lambda bj + lambda ck`
- `lambda sqrt(a^2+b^2+c^2)`

The answer is '`lambda a i+ lambda b j + lambda c k`'.

Can a vector `vec p` be divided by a real number `lambda`?

- Yes. Division is inverse of multiplication.
- No. Division of vector is not defined.

The answer is 'Yes. Division is inverse of multiplication.'

If the given vector is `vec p = ai+bj+ck` then

`vec p -: lambda`

`quad quad = 1/lambda xx vec p`

`quad quad = a/lambda i+b/lambda j+c/lambda k

*comprehensive information for quick review*

Jogger

*comprehensive information for quick review*

Jogger

dummy

**Multiplication of Vector by a scalar: ** For any vector `vec p = ai + bj+ ck in bbb V` and scalar `lambda in RR`

`lambda vec p= lambda ai+ lambda bj + lambda ck`

*practice questions to master the knowledge*

Exercise

*practice questions to master the knowledge*

Exercise

*your progress details*

Progress

*About you*

Progress

We have learned about addition of two or more vectors. Consider a vector being repeatedly added to itself. What is the result of the addition vector p + vector p?

1

2

3

4

The answer is "sum = 2 times vector p". If vector p = a i + b j + c k ; then vector p plus vector p = 2 a i + 2 b j + 2 c k. This equals 2 times vector p.

Repeated addition can be generalized to multiplication of vector by a scalar. Scalar multiplier is denoted with lambda to identify differently to the component values a, b, c. Note that the scalar multiplier and component values are real numbers. What is the result of lambda times vector p ; if vector p = ai + b j + c k?

1

2

3

4

The answer is ' lambda a i+ lambda b j + lambda c k '.

When vector is multiplied by a scalar, the vector scales up or down proportionally.

Multiplication of Vector by a scalar: For any vector p = a i + b j+ c k in vector space V ; and scalar lambda in real numbers. lambda times vector p = lambda a i+ lambda b j + lambda c k

can a vector p be divided by a real number lambda?

yes;s;inverse;multiplication

Yes. Division is inverse of multiplication.

no;not;defined

No. Division of vector is not defined.

The answer is "Yes. Division is inverse of multiplication". If the given vector is vector p = a i + b j + c k ; then vector p divided by lambda ; equals 1 by lambda, multiplied by vector p.