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Thought-Process to Discover Knowledge

Welcome to **nub****trek**.

Books and other education websites provide "matter-of-fact" knowledge. Instead, nubtrek provides a thought-process to discover knowledge.

In each of the topic, the outline of the thought-process, for that topic, is provided for learners and educators.

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Books and other education websites provide "matter-of-fact" knowledge. Instead, nubtrek provides a thought-process to discover knowledge.

In each of the topic, the outline of the thought-process, for that topic, is provided for learners and educators.

Read in the blogs more about the unique learning experience at nubtrek.continue

Welcome to **nub****trek**.

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think,

figure-out, &

learn.

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The content is presented in small-focused learning units to enable you to

think,

figure-out, &

learn.

To make best use of nubtrek, understand what is available.

nubtrek is designed to explain mathematics and science for young readers. Every topic consists of four sections.

nub,

trek,

jogger,

exercise.

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*summary of this topic*

Voice

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Home

» multiplication of a vector by a product of two scalars

→ `(lambda mu) vec p = lambda (mu vec p)`

*plain and simple summary*

nub

*plain and simple summary*

nub

dummy

• Multiplication of vector by a product of two scalars is equivalently multiplication by the scalars one by one.

*simple steps to build the foundation*

trek

*simple steps to build the foundation*

trek

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In this page, multiplication of a vector by product of scalars is explained.

Starting on learning the property "Multiplication of vector by Product of Scalars". ;; In this page, multiplication of a vector by product of scalars is explained.

Given that `vec p = ai+bj+ck` and `lambda, mu` where `a,b,c,lambda,mu in bbb R`, What will be the result of `(lambda mu) vec p `?

- `lambda(mu vec p)`
- `lambda vec p mu vec p`
- `mu vec p

The answer is '`lambda(mu vec p)`'. This is proven by multiplying the components individually by the scalar.

*comprehensive information for quick review*

Jogger

*comprehensive information for quick review*

Jogger

dummy

**Multiplication by Product of scalars: **Given a scalar as product of two scalars `lambda mu`,

`(lambda mu)vec p = lambda(mu vec p)`

*practice questions to master the knowledge*

Exercise

*practice questions to master the knowledge*

Exercise

*your progress details*

Progress

*About you*

Progress

Given that vector p = a i+b j+c k and lambda, mu ; where a,b,c,lambda,mu are in real numbers, What will be the result of lambda multiplied mu multiplied vector p ?

1

2

3

The answer is "lambda multiplied, mu times vector p". This is proven by multiplying the components individually by the scalar.

Multiplication of vector by a product of two scalars is equivalently multiplication by the scalars one by one

Multiplication by Product of scalars: Given a scalar as product of two scalars lambda and mu ;; lambda times mu multiplied vector p = lambda multiplied mu times vector p