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Thought-Process to Discover Knowledge

Welcome to **nub****trek**.

Books and other education websites provide "matter-of-fact" knowledge. Instead, nubtrek provides a thought-process to discover knowledge.

In each of the topic, the outline of the thought-process, for that topic, is provided for learners and educators.

Read in the blogs more about the unique learning experience at nubtrek.continue

Books and other education websites provide "matter-of-fact" knowledge. Instead, nubtrek provides a thought-process to discover knowledge.

In each of the topic, the outline of the thought-process, for that topic, is provided for learners and educators.

Read in the blogs more about the unique learning experience at nubtrek.continue

Welcome to **nub****trek**.

The content is presented in small-focused learning units to enable you to

think,

figure-out, &

learn.

**Just keep tapping** (or clicking) on the content to continue in the trail and learn. continue

The content is presented in small-focused learning units to enable you to

think,

figure-out, &

learn.

To make best use of nubtrek, understand what is available.

nubtrek is designed to explain mathematics and science for young readers. Every topic consists of four sections.

nub,

trek,

jogger,

exercise.

This captures the small-core of concept in simple-plain English. The objective is to make the learner to think about. continue

Trekking is bit hard, requiring one to sweat and exert. The benefits of taking the steps are awesome. In the trek, concepts are explained with exploratory questions and your thinking process is honed step by step. continue

This captures the essence of learning and helps one to review at a later point. The reference is available in pdf document too. This is designed to be viewed in a smart-phone screen. continue

This part does not have much content as of now. Over time, when resources are available, this section will have curated and exam-prep focused questions to test your knowledge. continue

*summary of this topic*

Voice

Voice

Home

» unit vector along the direction of vector is the vector divided by the magnitude

→ `hat p = (vec p)/(|vec p|)`

*plain and simple summary*

nub

*plain and simple summary*

nub

dummy

• Unit vector in the direction of a vector is the vector divided by its magnitude.

*simple steps to build the foundation*

trek

*simple steps to build the foundation*

trek

You are learning the free content, however do shake hands with a coffee to show appreciation.

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In this page, learn how to compute unit vector along a vector.

Starting on learning "Unit Vector along a vector". ;; In this page, learn how to compute unit vector along a vector.

Given the magnitude of a vector `|vec p| = 20` what is the magnitude of `(vec p)/5`?

- `20`
- `5`
- `4`
- `1/4`

The answer is '4'. It is `(|vec p|)/(|5|)`.

Given the magnitude of a vector `|vec p|` what is the magnitude of `(vec p)/(|vec p|)`?

- 1
- `|vec p|`
- `-1`
- `-|vec p|`

The answer is '1'.

Given two vectors `vec p` and `vec q`, how can you verify if the vectors are in same direction?

- directional cosines should be equal
- components along axes should be equal

The answer is 'Directional Cosines should be equal' along the respective axes.

Given two vectors `vec p` and `(vec p)/2`, are these in the same direction?

- Different directions
- Opposite directions
- Same direction

The answer is 'Same Direction'. Direction cosine of `(vec p)/2` is same as that of`vec p`. Please verify this by working out.

It is shown that

• magnitude of `(vec p)/(|vec p|)` is `1`

• direction of `(vec p)/(|vec p|)` is same as that of `vec p`

*comprehensive information for quick review*

Jogger

*comprehensive information for quick review*

Jogger

dummy

**Unit Vector along a Vector: ** The unit vector along a given vector `vec p` is given by

`hat p = (vec p)/(|p|)`

*practice questions to master the knowledge*

Exercise

*practice questions to master the knowledge*

Exercise

Find the unit vector along the direction of vector `vec p = 2i+2j+2k`

- `1/sqrt(3) (i+j+k)`
- `i+j+k`
- `2/sqrt(3) (i+j+k)`

The answer is '`1/sqrt(3) (i+j+k)`'.

*your progress details*

Progress

*About you*

Progress

Given the magnitude of a vector p = 20; what is the magnitude of vector p divided by 5 ?

20;twenty

20

5;five

5

4;four

4

1;one;by

1/4

The answer is "4".

Given the magnitude of a vector p, what is the magnitude of vector p divided by magnitude of vector p?

1;one

1

magnitude

magnitude of vector p

minus one;-1

minus 1

minus

minus magnitude of vector p

The answer is "1"

Given two vectors p and q, how can you verify if the vectors are in the same direction?

directional;cosines

directional cosines should be equal

components;along;axes

components along axes should be equal

The answer is 'Directional Cosines should be equal' along the respective axes.

Given two vectors p and p divided by 2, are these in the same direction?

different

Different directions

opposite

Opposite directions

same

Same direction

The answer is "Same Direction"

It is shown that magnitude of vector p divided by magnitude of vector p is 1 ;; and direction of vector p divided by magnitude of vector p is same as that of vector p.

Unit vector in the direction of a vector is the vector divided by its magnitude.

Unit Vector along a Vector: The unit vector along a given vector p is given by ;; hat p = vector p divided by magnitude of vector p.

Find the unit vector along the direction of vector p = 2 i + 2 j + 2 k

1

2

3

The answer is "1 by square root 3 multiplied i + j + k".