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Thought-Process to Discover Knowledge

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Books and other education websites provide "matter-of-fact" knowledge. Instead, nubtrek provides a thought-process to discover knowledge.

In each of the topic, the outline of the thought-process, for that topic, is provided for learners and educators.

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mathsWhole NumbersWhole Numbers: Multiplication and Division

Division : Simplified Procedure for Large Numbers

This page extends the division in first principles into a simplified procedure for division of large numbers, which is called division by place-value with de-grouping.



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division two digit numbers Consider the division `36-:3`. To perform the division, `36` is split into `3` parts and one part is counted.

division two digit numbers Considering the division `36-:3`. Splitting `36` into `3` parts is shown in the figure. Only one part is chosen, and other parts are shaded.

There are `1` tens and `2` units which together form the value `12` in one part.

division two digit numbers place-value-form Considering the division `36-:3`. The number `36` is given in the place value form in the figure. The splitting into equal parts is visualized and the division is performed as shown in the figure.

The tens place is divided first as `3-:3=1` and then the units place is divided as `6-:3=2`.

division with carryover two digit numbers Consider the division `52-:2`. That is, `52` is split into two equal parts as shown in the figure.

`5` tens are distributed as `2` each in the two parts. `1` ten part remains in the dividend. The `2` units parts are distributed as `1` each in the two parts.

`1` ten is equivalently `10` units and so can be distributed as `5` units each.

Considering the division `52-:2`. That is, `52` is split into two equal parts as shown in the figure.division two digit numbers Note that `1` ten remaining in dividend is de-grouped into `10` units and are placed `5` each. So the result of the division is `2` tens and `6` units, which is `26`.

Considering the division `52-:2`. The number `52` is given in the place value format in the figure.division of two digit numbers A simplified procedure, Division by Place-value is shown in the figure.

First the tens place division, `5-:2` is considered. `2xx2=4` and `1` ten remains.

The remaining `1` ten is converted to `10` units and combined with `2` units from units place of dividend. In the units place, `2xx6=12` is applied. The result is `26`.

division of larger two digit numbers Consider the division, `35-:4`. One `35` is shown in the figure.

The dividend can be either split into `4` equal parts or the simplified procedure can be used to divide in place-value form.

division of larger two digit numbers Considering the division: `35-:4`.

The `3` tens cannot be split into `4` equal parts. So the `3` tens are de-grouped into `30` units and combined with the `5` units.

division of larger two digit numbers Considering the division: `35-:4`. The value `35` is converted into `30` units and combined with the `5` units in the units place. Now, the units are distributed as shown in the figure.

One part makes `8` units and `3` units of dividend is remaining. The result of the division is, quotient `8` and remainder `3`.

division of larger two digit numbers place value Considering the division: `35-:4`. The numbers are given in place value in the figure. A simplified procedure is given in the figure. The result of the division is, quotient `8` and remainder `3`.

Division by Place-value -- Simplified Procedure : A number is divided using long division method as shown in the figure.simplified process for division Note: The procedure de-groups remaining tens into equivalent number of `10` units.

Solved Exercise Problem:

What is the quotient and remainder of `1111 -: 4`

  • quotient `22` and remainder `33`
  • quotient `277` and remainder `3`
  • quotient `277` and remainder `3`

The answer is "quotient `277` and remainder `3`"

Solved Exercise Problem:

What is the quotient and remainder of `3001 -: 3`

  • quotient `1` and remainder `1`
  • quotient `1000` and remainder `1`
  • quotient `1000` and remainder `1`

The answer is "quotient `1000` and remainder `1`"

                            
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